Panasonic AQ-C Relays دليل المستخدم

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AQ-C
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Miniature DIL 1A control
AQ-C RELAYS
type for PCBs
FEATURES TYPICAL APPLICATIONS
• Compact DIL type: • Compact AC motor, Solenoid,
L20 mm × W10 mm × H12.8 mm Magnet, Driver of magnetic valve
(.787×.394×.504 inch) • Copying equipment
• Excellent in noise resistance • NC machine, Robot
•Snubber circuit integrated •Programmable controller
• High dielectric strength: 2,500 V • Air conditioners
between input and output
•Reverse polarity type avai

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AQ-C 2. Output module Type Load voltage Input voltage Part No. 5 V DC AQC1A1 - ZT5 V DC 75 to 125 V AC 12 V DC AQC1A1 - ZT12 V DC 24 V DC AQC1A1 - ZT24 V DC AC output Zero-cross 5 V DC AQC1A2 - ZT5 V DC 75 to 250 V AC 12 V DC AQC1A2 - ZT12 V DC 24 V DC AQC1A2 - ZT24 V DC 5 V DC AQC1A1 - T 5 V DC 75 to 125 V AC 12 V DC

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AQ-C Characteristics [at 20°C 68°F; Input voltage ripple (output module) and output voltage ripple (input module): max. 1%] Input module Type AC Input DC Input Remarks Item Operate time, max. 20 ms 0.5 ms Input voltage: 24 V DC or 100V AC Output voltage: 24 V DC Release time, max 20 ms 0.5 ms Output current: 25mA 9 Insulation resistance, min. 10 Ω between input and output at 500 V DC Breakdown voltage 2,500 Vrms between input and output For 1 minute Destructive 10 to 55Hz double amplitude of 3 m

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AQ-C 5. Load current vs. ambient temperature characteristics for adjacent mounting 1.0 =20.32 mm .800 inch =12.7 mm 0.8 .500 inch 0.6 0.4 0.2 =Adjacent mounting pitch 0 –30 0 20 40 60 80 Ambient temperature, °C The CAD data of the products with a CAD Data mark can be downloaded from: http://panasonic-electric-works.net/ac DIMENSIONS (mm inch) PC board pattern (Copper-side view) 1. Input module (AC, DC) 10 10.16 7.62 CAD Data .394 .400 .300 2.7 Terminal 1 Terminal 8 .106 4-1.1 dia. 2.7

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AQ-C NOTE When used for the load less than rated In case the dummy resistor is not used, • Characteristics of residual voltage In the case of the load current less than keep in mind that the residual voltage vs. load impedance rated, malfunction may result from the becomes as follows: 100 f = 60 Hz residual voltage across the both ends of Example: Ve: Residual voltage the load even if the solid state relay is For the inductive load by the 5 mA load V: Power voltage 80 turned off. current and t